Hi,
Using TI:
*Note: 
probability that a particular call lasted between 110 and 180 seconds?
P(110>x<180)
Find z:
z = (110-240)/1.27 = -130/1.27
z = (180-240)/1.27 = -60/1.27
P(between smaller z and larger z): The syntax is normalcdf(smaller z, larger z).
normalcdf(-130/1.27, -60/1.27)
How many of the calls lasted less than 180 seconds or more than 300 seconds
1000(1 - normalcdf(-60/1.27, 60/1.27))