The basic graph of y = sin(x) has these 5 major points,
zero,max,zero,min,zero, which are:
(0,0), (
,1),
,0), (
,1), (
,0)
Your graph has the corresponding 5 major points, starting
with the point nearest the origin:
(
,0), (
,-3),
,0), (
,1), (
,0)
The period is
since the last x value of the five is
, and
the first of the five is
, so they have difference
=
=
=
,
same as the basic sine graph,
=
so there is no horizontal
stretching or shrinking.
Each of the 5 major x-coordinates of your graph is pi/4 less than its
corresponding x-coordinate on the basic sine graph:
=
=
=
=
=
So the horizontal shift, commonly called the phase shift, is
units to the
left. Therefore the equation of your graph will have (x-
) or
substituted
for x.
Each of the 5 major y-coordinates of the basic sine graph are 0,1,0,-1,0,
whereas the 5 corresponding major y-coordinates of your graph are 0,-3,0,3,0,
They are all multiplied by -3. The negative sign reflects the graph in the
x-axis and the 3 stretches it by a factor of 3 vertically. Therefore the right
side of the equation of your graph will have a factor of -3. So the equation
of your graph is found by starting with the basic sine graph:
y = sin(x)
Then replace the x by
and multiply the right side by -3, and get
y = -3sin
.
Edwin