SOLUTION: i need to solve this equation: 5^3x+4=4^2-x it would help if someone could show me the steps to it please

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Question 84159: i need to solve this equation:
5^3x+4=4^2-x
it would help if someone could show me the steps to it please
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
:
solve this equation:
Assume you mean:
5%5E%283x%2B4%29 = 4%5E%282-x%29
:
log(5%5E%283x%2B4%29) = log(4%5E%282-x%29); write the log of both sides
:
(3x+4)*log(5) = (2-x)*log(4); write the log equiv of exponents
:
.69897(3x+4) = .60206(2-x); found the log of 5 and 4
:
2.09691x + 2.79588 = 1.20412 - .60206x; multiplied what's inside the brackets
:
2.09691x + .60206x = 1.20412 - 2.79588
:
2.69897x = -1.59176
:
x = -1.59176/2.69897
:
x = -.5897657
:
:
Check solution on a good calc; substitute for x:
5^((3*-.5897657)+4) = 36.24
and
4^(2 + .5897657) = 36.24; minus a minus is a plus
:
Is this what you want?