SOLUTION: the sum of the measures of the three angles in a triangle is 180. the measure of the second angle is 10 more than the measure of the first angle. the measure of the third angle is

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Question 841336: the sum of the measures of the three angles in a triangle is 180. the measure of the second angle is 10 more than the measure of the first angle. the measure of the third angle is 100 less than three times the measure of the first angle. find the measure of each angle
Found 2 solutions by ewatrrr, stanbon:
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
the sum of the measures of the three angles in a triangle is 180.
the measure of the second angle is 10 more than the measure of the first anglehighlight_green%28x%29
the measure of the third angle is 100 less than three times the measure of the first anglehighlight_green%28x%29
x + (x+10) + (3x-100) = 180
x + x+10 + 3x-100 = 180°
5x - 90 = 180°
5x = 270°
x = 54° , the measure of the 1st angle.
2nd angle is 64° and 3rd angle is 62°
CHECKING our answer***
54° + 64° + 62° = 180°
Wish You the Best in your Studies.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
the sum of the measures of the three angles in a triangle is 180. the measure of the second angle is 10 more than the measure of the first angle. the measure of the third angle is 100 less than three times the measure of the first angle. find the measure of each angle
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Equations:
a + b + c = 180
b = a + 10
c = 3a - 100
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Sustitute for "b" and for "c" and solve for "a":
a + (a+10) + (3a-100) = 180
5a - 90 = 180
5a = 270
a = 54 degrees
b = a+10 = 64 degrees
c = 3a-100 = 62 degrees
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Cheers,
Stan H.
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