SOLUTION: how many liters of a 30% solution must be mixed with a 90 liters of 70% solution to get a 60% solution?

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Question 841235: how many liters of a 30% solution must be mixed with a 90 liters of 70% solution to get a 60% solution?
Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = liters of the 30% to add,

%2830x%2B70%2A90%29%2F%28x%2B90%29=60

To understand this clearly, see the lesson, http://www.algebra.com/tutors/Two-Part-Mixture-with-one-material-quantity-unknown.lesson?content_action=show_dev

Further Note:
The numerator represents the amount of dissolved material.
The denominator represents the total amount of mixture.