SOLUTION: Can you please help me solve: 1/2Log R + 1/3 LOG S - 1/4 LOG T
so far the answer I came up with is:
(square root r multiplied by third root of s) / over the fourth root of t
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-> SOLUTION: Can you please help me solve: 1/2Log R + 1/3 LOG S - 1/4 LOG T
so far the answer I came up with is:
(square root r multiplied by third root of s) / over the fourth root of t
Log On
Question 841190: Can you please help me solve: 1/2Log R + 1/3 LOG S - 1/4 LOG T
so far the answer I came up with is:
(square root r multiplied by third root of s) / over the fourth root of t
but I know it is wrong because a root cannot be at the bottom of a fraction and a square root and third root cannot even be multiplied Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! Your answer is correct as long as all of that is the argument of the log function.
A square root can be in the denominator of a fraction and you can multiply a square root and a third root.
