SOLUTION: x2 + 3x - 13 = 0 9x2 - 16 = 0 x2-7x+12=0 3x2

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Question 84113: x2 + 3x - 13 = 0
9x2 - 16 = 0
x2-7x+12=0
3x2 - 2x + 7 = 0
Answer by checkley75(3666) (Show Source):
You can put this solution on YOUR website!
USING THE QUADRATIC EQUATION WE GET:
X=(-3+-SQRT[3*3-4*1*-13])/2*1
X=(-3+-SQRT[9+52])/2
X=(-3+-SQRT61)/2
X=(-3+-7.81)/2
X=(-3+7.81)/2
X=4.81/2
X=2.405 ANSWER.
X=(-3-7.81)/2
X=-10.81/2
X=-5.405 ANSWER.
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9X^2-16=0
(3X+4)(3X-4)=0
3X+4=0
3X=-4
X=-4/3 ANSWER.
3X-4=0
3X=4
X=4/3 ANSWER.
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X^2-7X+12=0
(X-4)(X-3)=0
X-4=0
X=4 ANSWER.
X+4=0
X=-4 ANSWER.
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3X^2-2X+7=0
using the quadratic equation we get:
X=(2+-SQRT[-2*-2-4*3*7])/2*3
X=(2+-SQRT[4-84])/6
X=(2+-SQRT-80])/6
X=(2+-8.944i/6
X=2/6+8.944i/6
X=.333+1.49i ANSWER.
X=.333-1.49i ANSWER.

SOLUTION: x2 + 3x - 13 = 0 9x2 - 16 = 0 x2-7x+12=0 3x2 - 2x + 7 = 0