SOLUTION: this is my problem: let f(x)=5/x^2 and g(x)=6x=1 now it says to find (f 0 g)(x) and to find the domain of these my first instinct is to multiply the two equations together

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: this is my problem: let f(x)=5/x^2 and g(x)=6x=1 now it says to find (f 0 g)(x) and to find the domain of these my first instinct is to multiply the two equations together      Log On


   



Question 84105: this is my problem:
let f(x)=5/x^2 and g(x)=6x=1
now it says to find (f 0 g)(x) and to find the domain of these
my first instinct is to multiply the two equations together and the domain is the x value of the answer, is this the correct procedure?
if it isnt will someone please lay out the steps for solving it for me

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
let f(x)=5/x^2 and g(x)=6x+1
now it says to find (f 0 g)(x) and to find the domain of these
--------------
(fog)(x) means f[g(x)]
= f[6x+1]
= 5/(6x+1)^2
====================
Domain:
Since 6x+1 is in the denominator and since the denominator
cannot be zero, 6x+1 cannot be 0
So 6x cannot be -1
And finally, x cannot be -1/6
------
Domain of (fog)(x) is all Real Numbers except x=-1/6
===============
Cheers,
Stan H.