SOLUTION: A rectangle's length is 504 and 2/3 yards. The length is 6 yards shorter than twice the width. What is the area of the rectangle? I have to make a table that uses guess and che

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Question 841021: A rectangle's length is 504 and 2/3 yards. The length is 6 yards shorter than twice the width. What is the area of the rectangle?
I have to make a table that uses guess and check. I've tried doing that, but I'm not very good with fractions. So, maybe you can make a table or give me a way to figure out this problem.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A rectangle's length is 504 and 2/3 yards.
The length is 6 yards shorter than twice the width.
L = 2w - 6
5042%2F3 = 2W - 6
5042%2F3 + 6 = 2W
5102%2F3 = 2W
Divide 510 by 2; divide 2/3 by 2, resulting in:
2551%2F3 is the width
:
What is the area of the rectangle?
Change to improper fractions:
504(3) + 2 = 1514%2F3 is length
255(3) + 1 = 766%2F3 is the width
Area is length * width
1514%2F3 * 766%2F3 = 1159724%2F9 = 1288582%2F9 sq yds
(divide 9 into 1159724 using long division)