SOLUTION: the age of a man ten years ago was 35 years more than the twice the age of his son. After how many years from now will the man's age become twice his son's age?
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Question 840903: the age of a man ten years ago was 35 years more than the twice the age of his son. After how many years from now will the man's age become twice his son's age? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! let m = man's present age
let s = son's present age
:
the age of a man ten years ago was 35 years more than the twice the age of his son.
m - 10 = 2(s-10) + 35
m - 10 = 2s - 20 + 35
m - 10 = 2s + 15
m = 2s + 15 + 10
m = 2s + 25
:
After how many years from now will the man's age become twice his son's age?
let y = no. of years for this to be true
m + y = 2(s + y)
m + y = 2s + 2y
m = 2s + 2y - y
m = 2s + y
Look at the 1st equation, for this to be true; y = 25, right?
