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Question 840815: Please help me solve the following question . . . . Thanks!
Find 4 consecutive integers such that 3 times the sum of the first and third is 84 greater than the opposite of the second.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find 4 consecutive integers
n, (n+1), (n+2), (n+3)
:
such that 3 times the sum of the first and third is 84 greater than the opposite of the second
3[n + n+2)] = -(n+1) + 84
3(2n+2) = -n - 1 + 84
6n + 6 = -n + 83
6n + n = 83 - 6
7n = 77
n = 77/7
n = 11, 12, 13, 14 are the four integers:
:
:
See if that works
3(11+13) = -12 + 84
3(24) = 72
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