SOLUTION: James is now exactly twice as old as John. In three years Johns age will be two thirds of James' age. Two years ago Johns age was one fourth of James' age. what are their ages now?

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: James is now exactly twice as old as John. In three years Johns age will be two thirds of James' age. Two years ago Johns age was one fourth of James' age. what are their ages now?      Log On

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Question 840786: James is now exactly twice as old as John. In three years Johns age will be two thirds of James' age. Two years ago Johns age was one fourth of James' age. what are their ages now?

Answer by hamsanash1981@gmail.com(151) About Me  (Show Source):
You can put this solution on YOUR website!
Let james age be x and Johns age be y
at present x = 2 y.
Y + 3 = 2/3 (x + 3)
y + 3 = 2/3 ( 2Y + 3)
y + 3 = (4/3)Y + 2
4/3y - y = 3 - 2
Y/3 = 1
Y = 3
then x = 2 y
x = 2*3 => x= 6.
The Present age of James and John are 6 and 3.