SOLUTION: The measure of a big-screen television is given by the length of a diagonal across the screen. A 36-inch television has a width of 24.4in. Find the height of the screen to the near

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Question 84067This question is from textbook introductory algebra
: The measure of a big-screen television is given by the length of a diagonal across the screen. A 36-inch television has a width of 24.4in. Find the height of the screen to the nearest tenth of an inch.
 This question is from textbook introductory algebra

Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
The measure of a big-screen television is given by the length of a diagonal
across the screen. A 36-inch television has a width of 24.4in. Find the height
of the screen to the nearest tenth of an inch.



Just use the Pythagorean theorm:

           c² = a² + b²
          36² = 24.4² + b²
         1296 = 595.36 + b²
1296 - 595.36 = b²
       700.64 = b²
sqrt%28700.64%29 = b
  b = 26.46960521

or about 26.5 inches.

It's odd to have a TV screen higher
than it is wide, but that's the way
it works out.  Maybe the TV was 
lying on its side! J

Edwin