SOLUTION: mark reads at an average of 30 pages per hour, while mindy reads an average of 40 pages per hour. if mark starts reading a novel at 4:30 pm and mindy starts reading the same novel
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Question 84058: mark reads at an average of 30 pages per hour, while mindy reads an average of 40 pages per hour. if mark starts reading a novel at 4:30 pm and mindy starts reading the same novel 5:20 pm, what time will they be reading on the same page? Answer by Edwin McCravy(20054) (Show Source):
mark reads at an average of 30 pages per hour,
while mindy reads an average of 40 pages per
hour. if mark starts reading a novel at 4:30
pm and mindy starts reading the same novel
5:20 pm, what time will they be reading on the
same page?
Here is a problem that has exactly the same answer:
Mark rides his lightweight motorcycle at
30 miles per hour, while Mindy rides her
lightweight motorcycle at 40 miles per hour.
If mark start out at 4:30 pm and Mindy starts
out on the same road from the same starting
point at 5:20 pm, what time will Mindy catch
up with Mark?
Make this chart:
Distance Rate Time
Mark
Mindy
Let t = the number of hours after 4:30 when
Mindy catches Mark. So fill in t as Mark's time,
since he started at 4:30
Distance Rate Time
Mark t
Mindy
Fill in their rates of 30 mph and 40 mph
Distance Rate Time
Mark 30 t
Mindy 40
Now Mindy did not travel as long as Mark. It
is 50 minutes from 4:30 to 5:20, 50 minutes
is 50/60 or 5/6 of an hour, so her time is
5/6 less than Mark's or t-5/6. So fill that
in for Mindy's time:
Distance Rate Time
Mark 30 t
Mindy 40 t-
Now fill in the distances using D = RT
Distance Rate Time
Mark 30t 30 t
Mindy 40(t-) 40 t-
Mindy catches Mark when their
distances are equal. So the equation
is
30t = 40(t-)
Can you solve that? If not post again
asking how.
Solution: 10/3 hr. or 3 hours or
3 hours 20 minutes.
Answer to problem: 3 hours 20 minutes after
4:30PM is 7:50PM
That's the same answer as for the book reading.
Edwin