SOLUTION: Write equation for the line . Use slope intercept form if it its possible. # 1 through (-1,4) perpendicular to 9x+5y=11 this is what i have done so far am i correct 9x+5y

Algebra ->  Graphs -> SOLUTION: Write equation for the line . Use slope intercept form if it its possible. # 1 through (-1,4) perpendicular to 9x+5y=11 this is what i have done so far am i correct 9x+5y      Log On


   

Question 84055: Write equation for the line . Use slope intercept form if it its possible.
# 1
through (-1,4) perpendicular to 9x+5y=11
this is what i have done so far am i correct
9x+5y=11
5y=-9x+11
y=-(9)/(5)+(11)/(5)
so then i use the recipriocal slope which will be (5)/(9) and use the point that they gave me. so now i do the following:
y = mx+b
4 = (5)/(9) * (-1) +b
(41)/(9)=b
y= (5)/(9)x+(41)/(9)

#2
through (3,-5),parallel to y =4
for this one ihave no idea?

Found 2 solutions by jim_thompson5910, Edwin McCravy:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
#1 correct

#2
The equation of y=4 really looks like y=0x%2B4 where the slope is 0
Solved by pluggable solver: Finding the Equation of a Line Parallel or Perpendicular to a Given Line


Since any two parallel lines have the same slope we know the slope of the unknown line is 0 (its from the slope of y=0%2Ax%2B4 which is also 0). Also since the unknown line goes through (3,-5), we can find the equation by plugging in this info into the point-slope formula

Point-Slope Formula:

y-y%5B1%5D=m%28x-x%5B1%5D%29 where m is the slope and (x%5B1%5D,y%5B1%5D) is the given point



y%2B5=0%2A%28x-3%29 Plug in m=0, x%5B1%5D=3, and y%5B1%5D=-5



y%2B5=0%2Ax-%280%29%283%29 Distribute 0



y%2B5=0%2Ax-0 Multiply



y=0%2Ax-0-5Subtract -5 from both sides to isolate y

y=0%2Ax-5 Combine like terms

So the equation of the line that is parallel to y=0%2Ax%2B4 and goes through (3,-5) is y=0%2Ax-5


So here are the graphs of the equations y=0%2Ax%2B4 and y=0%2Ax-5



graph of the given equation y=0%2Ax%2B4 (red) and graph of the line y=0%2Ax-5(green) that is parallel to the given graph and goes through (3,-5)




So the line that is parallel to y=4 and goes through (3,-5) is y=-5
It's hard to see, but there are 2 horizontal lines at y=4 and y=-5

Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
Write equation for the line . Use slope intercept form if it its possible.
# 1
through (-1,4) perpendicular to 9x+5y=11
this is what i have done so far am i correct
9x+5y=11
5y=-9x+11
y=-(9)/(5)+(11)/(5)
so then i use the reciprocal slope with the opposite sign
which will be (5)/(9) and use the point that they gave me. so now i do the following:
y = mx+b
4 = (5)/(9) * (-1) +b
(41)/(9)=b
y= (5)/(9)x+(41)/(9) 

That one is correct!

#2
through (3,-5),parallel to y =4
for this one i have no idea?

y = 4 is this horizontal line

graph%28300%2C300%2C+-4%2C+10%2C+-7%2C+7%2C+4%29 

now plot the point (3,-5)

 
 
Now draw a green line parallel to
the given line through that point.
It will also be horizontal:



The equation of any horizontal line is y = b,
where b is the y-coordinate of any and every 
point on the line.  So since (3,-5) is on the 
line and it has y-coordinate -5, the equation
of the green line is y = -5.

Edwin