SOLUTION: Find the mystery # and the product when multiplied by itself. 1)I am the smallest 2 digit even # whose digits add to 4 2)I look the same backward and forward and so does my squar

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: Find the mystery # and the product when multiplied by itself. 1)I am the smallest 2 digit even # whose digits add to 4 2)I look the same backward and forward and so does my squar      Log On

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Question 840381: Find the mystery # and the product when multiplied by itself.
1)I am the smallest 2 digit even # whose digits add to 4
2)I look the same backward and forward and so does my square root
3)My square product is a 3 digit number

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Find the mystery # and the product when multiplied by itself.

2 digit even # are 10, 12,14,16,18,20,22,24%7D%7D%5D+and+so+on%0D%0A%0D%0Athe+%7B%7B%7Bsmallest whose digits add to 4 => has to be 22+
it looks the same backward and forward and so does sqrt%2822%29
product is a 3 digit number: 22%2A22=484