SOLUTION: I am in need of help: how do you solve -4/y-3 + 1 = -10/y^2-y-12? Please help me! Thank you very much! ( the problem is negative four divided by y minus three, plus one equals neg
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-> SOLUTION: I am in need of help: how do you solve -4/y-3 + 1 = -10/y^2-y-12? Please help me! Thank you very much! ( the problem is negative four divided by y minus three, plus one equals neg
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Question 84037: I am in need of help: how do you solve -4/y-3 + 1 = -10/y^2-y-12? Please help me! Thank you very much! ( the problem is negative four divided by y minus three, plus one equals negative ten divided by y to the second power minus y minus twelve) Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve -4/(y-3) + 1 = -10/(y^2-y-12)
Get a common denominator on the left side:
(-4+y-3)/(y-3) = -10/(y^2-y-12)
(y-7)/(y-3) = -10/(y^2-y-12)
Cross multiply to get:
(y-7)(y^2-y-12) = -10(y-3)
y^3-8y^2-5y+84 = -10y+30
y^3-8y^2+5y+54=0
I used a TI graphing calculator to find:
y=-2.08
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Cheers,
Stan H.
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