Question 840010: The equation, with restriction on x, is the terminal side of an angle theta on standard position.
-3x+y=0,x is less than or equal to 0
sin theta=
cos theta=
tan theta=
csc theta=
sec theta=
tan theta=
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The equation, with restriction on x, is the terminal side of an angle theta on standard position.
-3x+y=0,x is less than or equal to 0
Theta is in QII or QIII
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y = 3x
tan(theta) = 3 = y/x
Since x is negative, y must be negative.
y = -3 and x = -1
Therefore r = sqrt(3^2+1^2] = sqrt(10)
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sin theta= y/r = -3/sqrt(10)
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cos theta= = x/r = -1/sqrt(10)
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tan theta= y/x = 3
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Note: csc, sec, and tan are the inverse of sin, cos, and tan.
Cheers,
Stan H.
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csc theta=
sec theta=
tan theta=
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