SOLUTION: Heidi has $4.65 in nickles, dimes and quarters. She has 4 more quarters than dimes and five more nickles than quarters. How many coins of each type does she have?? Have been r

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Question 839801: Heidi has $4.65 in nickles, dimes and quarters. She has 4 more quarters than dimes and five more nickles than quarters. How many coins of each type does she have??
Have been racking my brain out for hours on this! Your help on showing how to work this problem would be greatly appreciated!!

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +n+ = number of nickels she has
Let +d+ = number of dimes she has
Let +q+ = number of quarters she has
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(1) +q+=+d+%2B+4+
(2) +n+=+q+%2B+5+
(3) +5n+%2B+10d+%2B+25q+=+465+ ( in cents )
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This is 3 equations and 3 unknowns, so it's solvable
(1) +d+=+q+-+4+
Substitute (1) and (2) into (3)
(3) +5%2A%28+q%2B5+%29+%2B+10%2A%28+q-4+%29+%2B+25q+=+465+
(3) +5q+%2B+25+%2B+10q+-+40+%2B+25q+=+465+
(3) +40q+=+465+-+25+%2B+40+
(3) +40q+=+480+
(3) +q+=+12+
and
(1) +d+=+q+-+4+
(1) +d+=+12+-+4+
(1) +d+=+8+
and
(2) +n+=+q+%2B+5+
(2) +n+=+12+%2B+5+
(2) +n+=+17+
17= number of nickels she has
8 = number of dimes she has
12 = number of quarters she has
check:
(3) +5n+%2B+10d+%2B+25q+=+465+
(3) +5%2A17+%2B+10%2A8+%2B+25%2A12+=+465+
(3) +85+%2B+80+%2B+300+=+465+
(3) +465+=+465+
OK