SOLUTION: Approximate, to the nearest 0.01 radian, all angles θ in the interval [0, 2π) that satisfy the equation. (Enter your answers as a comma-separated list.) (a)sin θ

Algebra ->  Trigonometry-basics -> SOLUTION: Approximate, to the nearest 0.01 radian, all angles θ in the interval [0, 2π) that satisfy the equation. (Enter your answers as a comma-separated list.) (a)sin θ      Log On


   



Question 839435: Approximate, to the nearest 0.01 radian, all angles θ in the interval [0, 2π) that satisfy the equation. (Enter your answers as a comma-separated list.)
(a)sin θ = 0.4798
(b)cos θ = −0.1201
(c)tan θ = −3.2206
(d)cot θ = 2.6318
(e)sec θ = 1.7957
(f)csc θ = −4.8123

Answer by stanbon(75887) About Me  (Show Source):
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Approximate, to the nearest 0.01 radian, all angles θ in the interval [0, 2π) that satisfy the equation. (Enter your answers as a comma-separated list.)
(a)sin θ = 0.4798
arcsin(0.4798) = 0.50 and pi-0.5 = 2.64
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(b)cos θ = −0.1201
arccos(-0.1201) = 1.69 or 2pi-1.69 = 4.59
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(c)tan θ = −3.2206
arctan(-3.2206) = 1.88 or 5.01
-----------------------------
(d)cot θ = 2.6318
arccot(2.6318) = 0.36 or pi+0.36 = 3.50
------------------------------------
(e)sec θ = 1.7957
arcsec(1.7957) = 0.98 or 2pi-0.98 = 5.31
-------------------------------------
(f)csc θ = −4.8123
arccsc(-4.8123) = 0.21 or pi-0.21 = 2.93
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Cheers,
Stan H.
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