SOLUTION: y+4=-4(x-2) What is the equation in standard form of a parallel line that passes through (0,-2)? -4x-y=4 Point slope form: y-y=m(x-x). (0,-2): X,Y

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: y+4=-4(x-2) What is the equation in standard form of a parallel line that passes through (0,-2)? -4x-y=4 Point slope form: y-y=m(x-x). (0,-2): X,Y       Log On


   

Question 839123: y+4=-4(x-2)
What is the equation in standard form of a parallel line that passes through (0,-2)?
-4x-y=4 Point slope form: y-y=m(x-x). (0,-2): X,Y
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
y+4=-4(x-2)
What is the equation in standard form
of a parallel line that passes through (0,-2)?
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Using the given equation::
y = -4x+8-4
y = -4x + 4
slope = -4
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Every parallel line must have slope = -4
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New line equation::
y = mx + b
m = -4 and f(0) = -2
Equation
y = -4x-2
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Cheers,
Stan H.