SOLUTION: Solve the equation sin(20)=1/2 on the interval 0<angle<2pi
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Question 839098
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Solve the equation sin(20)=1/2 on the interval 0
Answer by
stanbon(75887)
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Solve the equation sin(2t)=1/2 on the interval [0,2pi)
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Since sin(pi/6) = 1/2, 2t = pi/6 or (5/6)pi.
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t = pi/12 or (5/12)pi
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Cheers,
Stan H.