SOLUTION: FIND ALL POSSIBLE SOLUTIONS When Twice The Sum of 5 And An Unknown Number Is Subtracted From 8 Times The Unknown Number, The Result Is Equal To 4 Times The Sum Of 8 And Twice T

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: FIND ALL POSSIBLE SOLUTIONS When Twice The Sum of 5 And An Unknown Number Is Subtracted From 8 Times The Unknown Number, The Result Is Equal To 4 Times The Sum Of 8 And Twice T      Log On


   



Question 838767: FIND ALL POSSIBLE SOLUTIONS
When Twice The Sum of 5 And An Unknown Number Is Subtracted From 8 Times The Unknown Number, The Result Is Equal To 4 Times The Sum Of 8 And Twice The Unknown Number. Find The Number.

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
When Twice The Sum of 5 And An Unknown Numberhighlight_green%28x%29 Is Subtracted From 8 Times The Unknown Numberhighlight_green%28x%29
The Result Is Equal To 4 Times The Sum Of 8 And Twice The Unknown Numberhighlight_green%28x%29.
Find The Number.
Question states***
8x - 2(x+5)= 4(8 + 2x) |Solve for x
6x - 10 = 32 + 8x
-42 = 2x
x = -21, the number
CHECKING our answer***
168+-+2%2A-16+=+4%2A%28-34%29
-136 = -136
Wish You the Best in your Studies.