SOLUTION: (Can someone please help me with this question?) The function p(d)=1+d/33 gives the pressure in atmospheres (atm, at a depth d in the sea (d is in feet). Note that p(0)=atm, p(33)

Algebra ->  Functions -> SOLUTION: (Can someone please help me with this question?) The function p(d)=1+d/33 gives the pressure in atmospheres (atm, at a depth d in the sea (d is in feet). Note that p(0)=atm, p(33)      Log On


   



Question 838763: (Can someone please help me with this question?)
The function p(d)=1+d/33 gives the pressure in atmospheres (atm, at a depth d in the sea (d is in feet). Note that p(0)=atm, p(33)=2, and so on. Find the pressure at 100 feet.(Type an integer or a simplified fraction)
The pressure at 100 feet is ? atm.

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
p(d) = 1 + d/33
d is the depth in feet.
p is the pressure in atmospheric units of measure.

1 atm is defined as the pressure of the air at ground level.

per the formula, the deeper you go, the greater the pressure.
when d = 100, the equation becomes:
p(100) = 1 + 100/33
simplify this to get:
p(100) = 4.03030303 atmospheres or atmospheric units.

p(0) = 1 atm which means 1 unit of atmospheric pressure.
at 100 feet depth, the pressure is 4 times as much.

1 atm is roughly equivalent to 14.7 psi (pounds per square inch of force)
at a depth of 100 feet, 4.03 atm is roughly equivalent to 58.8 pounds per square inch

the deeper you go, the greater the pressure.
underwater vessels (like submarines) have a limit to the amount of pressure their hulls can stand before they start buckling.
if the underwater vessel goes too deep, it could it's tolerance for withstanding the pressure and suffer a catastrophic failure.

if you're interested, you can probably do some google searches on the internet involving what happens to submarines when they exceed their capacity to withstand the pressure at great depths.