SOLUTION: When Twice The Sum of 5 and an Unknown Number is Subtracted from 8 Times the Unknown Number, The Result is Equal to 4 Times the Sum of 8 and Twice the Unknown Number. Find the numb

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: When Twice The Sum of 5 and an Unknown Number is Subtracted from 8 Times the Unknown Number, The Result is Equal to 4 Times the Sum of 8 and Twice the Unknown Number. Find the numb      Log On


   

Question 838733: When Twice The Sum of 5 and an Unknown Number is Subtracted from 8 Times the Unknown Number, The Result is Equal to 4 Times the Sum of 8 and Twice the Unknown Number. Find the number.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
8x - 2(5 + x) = 4(8 + 2x)
8x - (10 + 2x) = 32 + 8x
6x - 10 = 8x + 32
-42 = 2x

x = -21