SOLUTION: solve the linear system with the method of elimination. 2x-3y= -4 3x+y=5

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Question 838707: solve the linear system with the method of elimination.
2x-3y= -4
3x+y=5

Found 2 solutions by Fombitz, ewatrrr:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
1.2x-3y=+-4
2.3x%2By=5
Multiply eq. 2 by 3 and add to eq. 1,
2x-3y%2B9x%2B3y=-4%2B15
11x=11
x=1
Then use either equation to solve for y
3%281%29%2By=5
3%2By=5
y=2

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
2x-3y= -4
3x+ y= 5 |Multiplying 2nd EQ by 3 & adding it to 1st EQ to eliminate y
11x= 11
x = 1 and y = 2 (3 + y = 5, y =2 )
CHECKING our answer***
Using: 2x-3y= -4
2 + -6 = -4