SOLUTION: a rectangle has a diagonal length of 15 ft and a width that is 3 more than its length. find the lendth, width and perineter of the rectangle
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Question 838693: a rectangle has a diagonal length of 15 ft and a width that is 3 more than its length. find the lendth, width and perineter of the rectangle Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Hi there,
Diagonal = 15 ft
Length = x ft
Width = x + 3 ft
Using Pythagoras theorem.
x^2 + (x + 3)^2 = 25^2
x^2 + x^2 + 6x + 9 = 225
2x^2 + 6x - 216 = 0
Divide throughout by 2
2(x^2 + 3x - 108 = 0)
2(x - 9)(x + 12) = 0
x = 9 or x = - 12.
As we cannot use a negative value
x = 9
and x + 3 = 12
x^2 + (x + 3)^2 = 25^2
9^2 + 12^2 = 25^2
81 + 144 = 225.
Hope this helps.:-)
