SOLUTION: find three consecutive even integers such that five times the third integer is six less than the sum of the first two.

Algebra ->  Divisibility and Prime Numbers -> SOLUTION: find three consecutive even integers such that five times the third integer is six less than the sum of the first two.      Log On


   

Question 838637: find three consecutive even integers such that five times the third integer is six less than the sum of the first two.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
The three consecutive integers are N,N%2B1,N%2B2.
5%28N%2B2%29=%28N%2BN%2B1%29-6
5N%2B10=2N-5
3N=-15
N=-5
N%2B1=-4
N%2B2=-3