SOLUTION: a ball is thrown upward with an initial velocity of 32 ft/sec from a height 768ft. its height h in feet after t seconds is given by
h(t)=-16t^2+32t+768. after how long will the b
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-> SOLUTION: a ball is thrown upward with an initial velocity of 32 ft/sec from a height 768ft. its height h in feet after t seconds is given by
h(t)=-16t^2+32t+768. after how long will the b
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Question 838504: a ball is thrown upward with an initial velocity of 32 ft/sec from a height 768ft. its height h in feet after t seconds is given by
h(t)=-16t^2+32t+768. after how long will the ball reach the ground? Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! h(t)=-16t^2+32t+768. after how long will the ball reach the ground?
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When h(t) = 0
h(t)=
Solve for t, use the positive value.
