SOLUTION: Rewrite the following without logarithms: f) Log W = 2(logA +logW) – (log32 +2logπ+2log r+log c)

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Question 837701: Rewrite the following without logarithms:
f) Log W = 2(logA +logW) – (log32 +2logπ+2log r+log c)

Answer by Theo(13342) About Me  (Show Source):
You can put this solution on YOUR website!
you will get the following by using the properties of logarithms.


          2 * (log(A) + log(W) is equal to:
          log( (AW)^2 ) which is equal to:
          log(A^2*W^2)



           log(32) + 2*log(pi) + 2*log(r) + log(c) is equal to:
           log(32) + log(pi^2) + log(r^2) + log(c) which is equal to:
           log (32*pi^2*r^2*c)



your equation becomes:

           log(W) = log(A^2*W^2) - log(32*pi^2*r^2*c)

this becomes:

           log(W) = log        (         A^2*W^2        )
                                    ------------------
                                      32*pi^2*r^2*c

this means that:
                         W =              A^2*W^2        
                                    ------------------
                                      32*pi^2*r^2*c


this is because if log(a) = log(b), then a must be equal to b.



the properties of log that were used are:

log(a^b) = b*log(a)
log(a*b) = log(a) + log(b)
log(a/b) = log(a) - log(b)
if log(a) = log(b), then a must be equal to b.