SOLUTION: find the foci for the conic (x/5)^2-(y/12)^2=1

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Question 837668: find the foci for the conic (x/5)^2-(y/12)^2=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
find the foci for the conic (x/5)^2-(y/12)^2=1
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This is an equation of a hyperbola with horizontal transverse axis and center at the origin.
Its standard form of equation: x%5E2%2Fa%5E2-y%5E2%2Fb%5E2=1
a^2=5^2=25
b^2=12^2=144
c^2=a^2+b^2=25+144=169
c=√169=13
foci: (0±c,0)=(0±13,0)=(-13,0) and (13,0)