SOLUTION: the stopping distance d in feet for a car traveling at a speed of s miles per hour depends on car road conditions. here are two possible stopping distance formulas: d=3s and d=0.0

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Question 837447: the stopping distance d in feet for a car traveling at a speed of s miles per hour depends on car road conditions. here are two possible stopping distance formulas: d=3s and d=0.05s^2+s.
a.write and solve an equation to answer the question, "for what speed(s) do the two functions predict the same stopping distance?


b. in what ways are the patterns on change in stopping distance predicted by the two functions as speed increases similar and in what ways are they different? how do the function graphs illustrate the patterns you notice?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
the stopping distance d in feet for a car traveling at a speed of s miles per hour depends on car road conditions.
here are two possible stopping distance formulas: d=3s and d=0.05s^2+s.
:
a.write and solve an equation to answer the question, "for what speed(s) do the two functions predict the same stopping distance?
:
We can write the equations as equal to each other
.05s^2+s = 3s
simplify, divide both sides by s
.05s + 1 = 3
.05s = 3 - 1
.05s = 2
s = 2/.05
s = 40 mph, both equations will have the same stopping distance
:
:
Graphically
+graph%28+300%2C+200%2C+-20%2C+100%2C+-100%2C+400%2C+.05x%5E2%2Bx%2C+3x%2C+120%29+
note the stopping distance is 120 ft at 40 mph for both equations