SOLUTION: a box contains 3 red marbles and 6 blue marbles and 1 white marble. the marbles are selected at random,, one at a time, and are not replaced. find the probability

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Question 837396: a box contains 3 red marbles and 6 blue marbles and 1 white marble. the marbles are selected at random,, one at a time, and are not replaced. find the probability

Found 2 solutions by Fombitz, Edwin McCravy:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Probability of what??
Please repost.

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!
A box contains 3 red marbles and 6 blue marbles and 1 white marble.
I will guess at something you may have wanted that you didn't tell us.
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A. TWO marbles are selected at random, and the first one is not replaced
   before the second one is drawn. Find the probability:

10. P(Blue 1st then Red 2nd) = %286%2F11%29%283%2F10%29 = 18%2F110 = 9%2F55

11. P(Blue 1st then Blue 2nd) = %286%2F11%29%285%2F10%29 = 30%2F110 = 3%2F11
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B. THREE marbles are selected at random,, one at a time, and are not 
   replaced.  Find the probability:

12. P(Red 1st, White 2nd, then Blue 3rd) = %283%2F11%29%281%2F10%29%286%2F9%29 = 18%2F990 = 1%2F55 

13. P(Red 1st, Red 2nd then Red 3rd) = %283%2F11%29%282%2F10%29%281%2F9%29 = 6%2F990 = 1%2F165

14. P(White 1st, Red 2nd, then White 3rd) = 0 
    That's because there is only 1 white marble. Since we don't replace the
    first white marble, it is impossible to get it third.

Edwin