Question 836523: What are the x-intercepts of -x^4+16x^2 ?
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! What are the x-intercepts of -x^4+16x^2 ?
equation is:
y=-x^4+16x^2
.
to find x-intercepts, set y=0 and solve for x:
0=-x^4+16x^2
0=x^4-16x^2
0=x^2(x^2-16)
0=x^2(x^2-4^2)
0=x^2(x-4)(x+4)
x = {-4,0,4}
.
x-intercepts are at:
(-4,0), (0,0), and (4,0)
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