SOLUTION: Please help me solve for x! {{{ 5^(2x+3) = 8^(x-4) }}}

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me solve for x! {{{ 5^(2x+3) = 8^(x-4) }}}      Log On


   

Question 836473: Please help me solve for x! +5%5E%282x%2B3%29+=+8%5E%28x-4%29+
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Do it like this one.
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+a%5E%28x-5%29+=+b%5E%283x%2B9%29+
%28x-5%29%2Alog%28a%29+=+%283x%2B9%29%2Alog%28b%29+
x*log(a) - 5log(a) = 3x*log(b) + 9log(b)
x*log(a) - 3x*log(b) = 5log(a) + 9log(b)
x*(log(a) - 3log(b)) = 5log(a) + 9log(b)
x+=+%285log%28a%29+%2B+9log%28b%29%29%2F%28log%28a%29+-+3log%28b%29%29