SOLUTION: factor out completely 8x^3+27

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Question 836292: factor out completely
8x^3+27
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Use the sum of cubes rule to get...

8x^3+27

(2x)^3+3^3

(2x+3)((2x)^2-2x*3+(3)^2)

(2x+3)(4x^2-6x+9)