SOLUTION: Classify the polygon if the sum of the exterior angles is twice the sum of the interior angles. I know the polygon is a triangle, but how do I set up the equation to find the answe

Algebra ->  Polygons -> SOLUTION: Classify the polygon if the sum of the exterior angles is twice the sum of the interior angles. I know the polygon is a triangle, but how do I set up the equation to find the answe      Log On


   

Question 836225: Classify the polygon if the sum of the exterior angles is twice the sum of the interior angles. I know the polygon is a triangle, but how do I set up the equation to find the answer?
Answer by Edwin McCravy(20059) About Me  (Show Source):
You can put this solution on YOUR website!
The sum of the interior angles of an n-sided polygon is given by the
formula (n-2)·180°.

The sum of the exterior angles of ANY polygon is 360°.

We are told that the sum of the exterior angles is twice the sum of the interior angles:

360° = 2[(n-2)180°]

360 = 360(n-2)

Divide both sides by 360

1 = n-2

Add 2 to both sides

3 = n

Edwin