SOLUTION: divide the fractions: 6p-18/9p divided by 3p-9/p^2+2p I really need somones help with this.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: divide the fractions: 6p-18/9p divided by 3p-9/p^2+2p I really need somones help with this.      Log On


   

Question 83619: divide the fractions:
6p-18/9p divided by 3p-9/p^2+2p
I really need somones help with this.
Answer by Edwin McCravy(20054) About Me  (Show Source):
You can put this solution on YOUR website!

divide the fractions:
6p-18/9p divided by 3p-9/p^2+2p 
I really need somones help with this.

 divide the fractions:
%286p-18%29%2F%289p%29 ÷ %283p-9%29%2F%28p%5E2%2B2p%29

Invert the second fraction and change ÷ to ×

%286p-18%29%2F%289p%29 × %28p%5E2%2B2p%29%2F%283p-9%29 

Factor the two numerators and the bottom right
denominator:

%286%28p-3%29%29%2F%289p%29 × %28p%28p%2B2%29%29%2F%283%28p-3%29%29

Indicate the multiplication of the numerators
and denominators:

(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)

Cancel the 3 in the bottom into the 6 in the top

 2
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
       1

Cancel the (p-3)'s

 2   1
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
       1   1

Cancel the p's

 2   1   1
(6)(p-3)(p)(p+2)
  (9p)(3)(p-3)
    1  1   1

All that left is

 2(p+2)
   9

which you can either leave in that
form or else distribute the 2 in the 
top like this:

  2p+4
    9

Edwin