SOLUTION: I need to figure out how to find the perimeter of a Rhombus that has sides of AB=8x+10 and BC=4x+30. I don't know how to figure this question out with letters. Could you please ex
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-> SOLUTION: I need to figure out how to find the perimeter of a Rhombus that has sides of AB=8x+10 and BC=4x+30. I don't know how to figure this question out with letters. Could you please ex
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Question 836180: I need to figure out how to find the perimeter of a Rhombus that has sides of AB=8x+10 and BC=4x+30. I don't know how to figure this question out with letters. Could you please explain to me how to do it cause I am so confused. Answer by richard1234(7193) (Show Source):
You can put this solution on YOUR website! The sides of a rhombus are equal, so AB = BC. 8x+10 = 4x+30 --> x = 5. Plugging in x=5, we have AB = 50. The perimeter is 4*50 = 200.
