SOLUTION: A rod 7 feet long is supported at a point 6 inches from the center. A weight of x pounds is attached at the end of the shorter lever arm, a weight of y pounds at the other end. In
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Question 836142: A rod 7 feet long is supported at a point 6 inches from the center. A weight of x pounds is attached at the end of the shorter lever arm, a weight of y pounds at the other end. In order to make the rod balance it is necessary to attach a 10 pound weight at a distance of 1 foot from the weight of x pounds. If the weight x and y are interchanged it is necessary to place a 2 pound weight, with the y pound weight to effect a balance. Find x and y (a) neglecting the weight of the rod, (b) assuming that the rod weighs k pound per foot. Answer by new_user(6) (Show Source):
You can put this solution on YOUR website! Use the principle:
(Load) x (Load Arm) = (Effort) x (Effort Arm)
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