SOLUTION: 1. A tree 50-feet tall casts a shadow 30-feet long.
Mary's shadow is 27-inches long. How tall is Mary?
2. A reprint of a picture in a photographer exhibit is 8-inches wide and
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-> SOLUTION: 1. A tree 50-feet tall casts a shadow 30-feet long.
Mary's shadow is 27-inches long. How tall is Mary?
2. A reprint of a picture in a photographer exhibit is 8-inches wide and
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Question 83599: 1. A tree 50-feet tall casts a shadow 30-feet long.
Mary's shadow is 27-inches long. How tall is Mary?
2. A reprint of a picture in a photographer exhibit is 8-inches wide and 12-inches long. If the actual picture is 60- inches long, how wide is it? Answer by uma(370) (Show Source):
You can put this solution on YOUR website! 1) This problem is worked out keeping in mind that the shadow length is proportionate to the ht of the object.
Let Mary's height be x inches.
Then 50 : 30 :: x : 27
==> 30x = 50 * 27
==> x = 50 * 27/30
= 45
Thus Mary is 45 inches tall.
2)Let the width of the actual picture be w inches.
Then the proportion would be- 8: 12 :: w : 60
==> 12w = 8 x 60
==> w = 8 x 60/12
= 40
Thus the picture is 40 inches wide
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