SOLUTION: Find the point (0,b) on the y-axis that is equidistant from the points 94,4) and (5,-4). b=?

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Question 835893: Find the point (0,b) on the y-axis that is equidistant from the points 94,4) and (5,-4).
b=?
Found 2 solutions by josmiceli, Fombitz:
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(0,b) to (4,4) is
+d%5B1%5D+=+sqrt%28+%284+-+0+%29%5E2+%2B+%28+4+-+b+%29%5E2+%29+
(0,b) to (5,-4) is
+d%5B2%5D+=+sqrt%28+%28+5+-+0+%29%5E2+%2B+%28+-4+-+b+%29%5E2%29+
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Square both sides
+4%5E2+%2B+%28+4-b+%29%5E2+=+5%5E2+%2B+%28+-4+-b+%29%5E2+
+16+%2B+%28+4-b+%29%5E2+=+25+%2B+%28+-4-b+%29%5E2+
+%284-b%29%5E2+-+%28+-4-b+%29%5E2+=+25+-+16+
Solve for b -you can finish

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Use the distance formula,
D%5E2=%28x%5B2%5D-x%5B1%5D%29%5E2%2B%28y%5B2%5D-y%5B1%5D%29%5E2%29
%284-0%29%5E2%2B%284-b%29%5E2=%285-0%29%5E2%2B%28-4-b%29%5E2
16%2B16-8b%2Bb%5E2=25%2B16%2B8b%2Bb%5E2
b%5E2-8b%2B32=b%5E2%2B8b%2B41
16b=9
highlight%28b=-9%2F16%29