SOLUTION: Lucy is six years older than Kathy. In two years, Lucy will be twice as old as Kathy. Find their ages now. L = Lucy's age K = Kathy's age L = K + 6 L + 2 = 2K Am I sett

Algebra ->  Customizable Word Problem Solvers  -> Age -> SOLUTION: Lucy is six years older than Kathy. In two years, Lucy will be twice as old as Kathy. Find their ages now. L = Lucy's age K = Kathy's age L = K + 6 L + 2 = 2K Am I sett      Log On

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Question 835771: Lucy is six years older than Kathy. In two years, Lucy will be twice as old as Kathy. Find their ages now.
L = Lucy's age
K = Kathy's age
L = K + 6
L + 2 = 2K
Am I setting this up right ?

Answer by josgarithmetic(39618) About Me  (Show Source):
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In two years, the expressions for Lucy's and Kathy's ages are L+2, and K+2.
At that time, Lucy will be twice as old as Kathy, so L+2=2(K+2).