SOLUTION: A metallurgist needs to make 12.4 lb. of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with anther metal that is 40% gold. How much of ea
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Question 835687: A metallurgist needs to make 12.4 lb. of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with anther metal that is 40% gold. How much of each should he use? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! A metallurgist needs to make 12.4 lb. of an alloy containing 50% gold. He is going to melt and combine one metal that is 60% gold with anther metal that is 40% gold. How much of each should he use?
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Equations:
Quantity:: f + s = 12.4 lbs
Gold:::: 40f +60s = 50*12.4
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Modify for elimination:
4f + 4s = 4*12.4
4f + 6s = 5*12.4
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Subtract and solve for "s":
2s = 12.4
s = 6.2 lbs (amt. of 60% alloy needed)
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Solve for "f":
f + 6.2 = 12.4
f = 6.2 lbs (amt. of 40% alloy needed)
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Cheers,
Stan H.
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