SOLUTION: Simplify and ractionalize all denominators:
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
I really dont know where to start with this question, I would like to see all the steps and the
Algebra ->
Square-cubic-other-roots
-> SOLUTION: Simplify and ractionalize all denominators:
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
I really dont know where to start with this question, I would like to see all the steps and the
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Question 83550: Simplify and ractionalize all denominators:
3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
I really dont know where to start with this question, I would like to see all the steps and the answer so i can break it down and understand each step. Thank you in advance! Found 2 solutions by stanbon, Edwin McCravy:Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 3b[SQRT(27a^5b)] + 2a[SQRT(3a^3b^3)]
Simplify the SQRT factors to get:
= 3b[3a^2(sqrt3ab)] + 2a[a^2b^2(sqrt3ab)]
Factor out the common factor of sqrt3ab to get:
= [9a^2 + 2a^3b^2][sqrt3ab]
Cheers,
Stan H.
Stanbon's solution to your problem is incorrect.
Simplify and ractionalize all denominators:
There are no denominators to rationalize, so we just simplify this one
Break up what's under the radicals completely into prime factors:
Break up into primes as
Break up into primes
Substitute these under the radicals:
+
Since the index of the root is 2 (square root) we group all
like factors by twos (pairs) that we can like this. We will
often have factors left over that would not pair up:
+
Each pair of like factors can be written as a square
+
Take out each square from under the radical out front of the radical,
like this, leaving what didn't pair up under the radical:
+
Simplify what's in front of the radicals:
+
Now you can factor out GCF = ( + )
Edwin
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