SOLUTION: For 0<(theta)<pi/2,find the values of the trigonometric functions based on the given one.
Note: the answer must be given as a fraction.
If sec(theta)=9/5 the
csc(theta)=
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-> SOLUTION: For 0<(theta)<pi/2,find the values of the trigonometric functions based on the given one.
Note: the answer must be given as a fraction.
If sec(theta)=9/5 the
csc(theta)=
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Question 835455: For 0<(theta)
Note: the answer must be given as a fraction.
If sec(theta)=9/5 the
csc(theta)=
Sin(theta)=
cos(theta)=
tan(theta)=
cot(theta)= Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! For 0<(theta) Note: the answer must be given as a fraction.
If sec(theta)=9/5 the
csc(theta)=
Sin(theta)=
cos(theta)=
tan(theta)=
cot(theta)=
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sec(theta)=9/5=hypotenuse/adjacent side
opposite side=√(9^2-5^2)=√(81-25)=√56
csc(theta)=hypotenuse/opposite side=9/√56=9√56/56
Sin(theta)=1/csc theta=√56/9
cos(theta)=1/sec theta=5/9
tan(theta)=opposite side/adjacent side=√56/5
cot(theta)=1/tan theta
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