You can put this solution on YOUR website! hw much 5% acid must be added to 15% acid to get 50mL of 8% acid?
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Using 2 variables you get:
Quantity: f + t = 40mL
Acid:::: 5f+15t = 8*50
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Modify for elimination:
15f + 15t = 15*40
5f + 15t = 8*50
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Subtract and solve for "f":
10f = 200
f = 20 mL (amt of 5% solution needed)
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Cheers,
Stan H.
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