Question 835348: Assume that there is an urn containing eight $50 bills, seven $20 bills, six $10 bills, five $5 bills, and one $1 bill and that the bills all have different serial numbers so that they can be distinguished from each other. A person reaches into the urn and withdraws one bill and then another.
(a) In how many ways can two $20 bills be withdrawn?
(b) How many different outcomes are possible?
(c) What is the probability of selecting two $20 bills? (Enter your probability as a fraction.)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Assume that there is an urn containing eight $50 bills, seven $20 bills, six $10 bills, five $5 bills, and one $1 bill and that the bills all have different serial numbers so that they can be distinguished from each other. A person reaches into the urn and withdraws one bill and then another.
(a) In how many ways can two $20 bills be withdrawn?
Ans: 7C2 = = 21 ways
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(b) How many different outcomes are possible?
Ans: 27C2 = 351 ways
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(c) What is the probability of selecting two $20 bills? (Enter your probability as a fraction.)
Ans: 21/351
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Cheers,
Stan H.
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