SOLUTION: f(x)=-6x^2-4x-5
This is what I have gotten so far:
-b/2a= -(-4)/2(-6)= 4/-12= (-1/3,
y=-6(-1/3)^2-4(1/3)-5
y=-6(-1/9)-4(1/3)-5
y= -6/9-4/3-
I'm still trying to find the
Algebra ->
Quadratic-relations-and-conic-sections
-> SOLUTION: f(x)=-6x^2-4x-5
This is what I have gotten so far:
-b/2a= -(-4)/2(-6)= 4/-12= (-1/3,
y=-6(-1/3)^2-4(1/3)-5
y=-6(-1/9)-4(1/3)-5
y= -6/9-4/3-
I'm still trying to find the
Log On
Question 835206: f(x)=-6x^2-4x-5
This is what I have gotten so far:
-b/2a= -(-4)/2(-6)= 4/-12= (-1/3,
y=-6(-1/3)^2-4(1/3)-5
y=-6(-1/9)-4(1/3)-5
y= -6/9-4/3-
I'm still trying to find the y-coordinate. I'm not sure if I need to find the common denominator or what. Please help me? Answer by Alan3354(69443) (Show Source):
