SOLUTION: I need help on this question. What is the equation of the line that passes through (–2, 4) and is perpendicular to 2x + 3y = –6?
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You can put this solution on YOUR website! What is the equation of the line that passes through (–2, 4) and is perpendicular to 2x + 3y = –6?
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1st: Find the slope of the given line:
3y = -2x-6
y = (-2/3)x - 2
slope = -2/3
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2nd: A perpendicular line must have slope = 3/2
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Form: y = mx + b
Substitute and solve for "b":
4 = (3/2)(-2) + b
4 = -3 + b
b = 7
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Equation:
y = (3/2)x + 7
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Cheers,
Stan H.
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